Base | Representation |
---|---|
bin | 11001110100001111010011… |
… | …000011001100111000101110 |
3 | 112220000102011121012200210210 |
4 | 121310033103003030320232 |
5 | 104340223432313122200 |
6 | 1041252003234443250 |
7 | 32626031600125524 |
oct | 3164172303147056 |
9 | 486012147180723 |
10 | 113541001301550 |
11 | 331a5517255049 |
12 | 1089900b733526 |
13 | 4b47b415a60b4 |
14 | 20075b15d4314 |
15 | d1d6de40d650 |
hex | 6743d30cce2e |
113541001301550 has 24 divisors (see below), whose sum is σ = 281581683228216. Its totient is φ = 30277600347040.
The previous prime is 113541001301531. The next prime is 113541001301647. The reversal of 113541001301550 is 55103100145311.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 378470004189 + ... + 378470004488.
It is an arithmetic number, because the mean of its divisors is an integer number (11732570134509).
Almost surely, 2113541001301550 is an apocalyptic number.
113541001301550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113541001301550 is an abundant number, since it is smaller than the sum of its proper divisors (168040681926666).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113541001301550 is a wasteful number, since it uses less digits than its factorization.
113541001301550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 756940008692 (or 756940008687 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 30.
Adding to 113541001301550 its reverse (55103100145311), we get a palindrome (168644101446861).
The spelling of 113541001301550 in words is "one hundred thirteen trillion, five hundred forty-one billion, one million, three hundred one thousand, five hundred fifty".
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