Base | Representation |
---|---|
bin | 11001111011000110011010… |
… | …100101001011110000000101 |
3 | 112221200111012011210002010101 |
4 | 121323012122211023300011 |
5 | 104420440100034423140 |
6 | 1042252341454524101 |
7 | 33005063020440340 |
oct | 3173063245136005 |
9 | 487614164702111 |
10 | 114012500311045 |
11 | 33367480142536 |
12 | 10954477806631 |
13 | 4b80442a9523b |
14 | 202233d4d5457 |
15 | d2aad7d1899a |
hex | 67b19a94bc05 |
114012500311045 has 16 divisors (see below), whose sum is σ = 163158261315840. Its totient is φ = 74780869768704.
The previous prime is 114012500311027. The next prime is 114012500311057. The reversal of 114012500311045 is 540113005210411.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 114012500311045 - 221 = 114012498213893 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70815216780 + ... + 70815218389.
It is an arithmetic number, because the mean of its divisors is an integer number (10197391332240).
Almost surely, 2114012500311045 is an apocalyptic number.
It is an amenable number.
114012500311045 is a deficient number, since it is larger than the sum of its proper divisors (49145761004795).
114012500311045 is a wasteful number, since it uses less digits than its factorization.
114012500311045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 141630435204.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 114012500311045 its reverse (540113005210411), we get a palindrome (654125505521456).
The spelling of 114012500311045 in words is "one hundred fourteen trillion, twelve billion, five hundred million, three hundred eleven thousand, forty-five".
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