11401300111 has 4 divisors (see below), whose sum is σ = 11401560000. Its totient is φ = 11401040224.

The previous prime is 11401300109. The next prime is 11401300147. The reversal of 11401300111 is 11100310411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11401300111 - 2¹ = 11401300109 is a prime.

It is a super-2 number, since 2×11401300111² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11401300091 and 11401300100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11401300511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46111 + ... + 157888.

It is an arithmetic number, because the mean of its divisors is an integer number (2850390000).

Almost surely, 2^11401300111 is an apocalyptic number.

11401300111 is a deficient number, since it is larger than the sum of its proper divisors (259889).

11401300111 is an equidigital number, since it uses as much as digits as its factorization.

11401300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259888.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 11401300111 its reverse (11100310411), we get a palindrome (22501610522).

The spelling of 11401300111 in words is "eleven billion, four hundred one million, three hundred thousand, one hundred eleven".