1140131112 has 32 divisors (see below), whose sum is σ = 3017995200. Its totient is φ = 357688064.

The previous prime is 1140131099. The next prime is 1140131131. The reversal of 1140131112 is 2111310411.

It is a junction number, because it is equal to n+sod(n) for n = 1140131091 and 1140131100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1396812 + ... + 1397627.

It is an arithmetic number, because the mean of its divisors is an integer number (94312350).

Almost surely, 2^1140131112 is an apocalyptic number.

1140131112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1140131112 is an abundant number, since it is smaller than the sum of its proper divisors (1877864088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1140131112 is a wasteful number, since it uses less digits than its factorization.

1140131112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2794465 (or 2794461 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 1140131112 is about 33765.8275775969. The cubic root of 1140131112 is about 1044.6839736364.

Adding to 1140131112 its reverse (2111310411), we get a palindrome (3251441523).

The spelling of 1140131112 in words is "one billion, one hundred forty million, one hundred thirty-one thousand, one hundred twelve".