1140213311320 has 16 divisors (see below), whose sum is σ = 2565479950560. Its totient is φ = 456085324512.

The previous prime is 1140213311311. The next prime is 1140213311333. The reversal of 1140213311320 is 231133120411.

It is a super-2 number, since 2×1140213311320² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1140213311291 and 1140213311300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14252666352 + ... + 14252666431.

It is an arithmetic number, because the mean of its divisors is an integer number (160342496910).

Almost surely, 2^{1140213311320} is an apocalyptic number.

1140213311320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1140213311320 is an abundant number, since it is smaller than the sum of its proper divisors (1425266639240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1140213311320 is a wasteful number, since it uses less digits than its factorization.

1140213311320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28505332794 (or 28505332790 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1140213311320 its reverse (231133120411), we get a palindrome (1371346431731).

The spelling of 1140213311320 in words is "one trillion, one hundred forty billion, two hundred thirteen million, three hundred eleven thousand, three hundred twenty".