Base | Representation |
---|---|
bin | 1010010111101111111110… |
… | …0110001111110110000000 |
3 | 1111101010110211112200000221 |
4 | 2211323333212033312000 |
5 | 2443312103120420112 |
6 | 40130305400552424 |
7 | 2254564140543652 |
oct | 245737746176600 |
9 | 44333424480027 |
10 | 11403131420032 |
11 | 36a704a453550 |
12 | 1342005782714 |
13 | 64940673b851 |
14 | 2b5cb35906d2 |
15 | 14b94ce55e07 |
hex | a5eff98fd80 |
11403131420032 has 64 divisors (see below), whose sum is σ = 24802740905040. Its totient is φ = 5178981744640.
The previous prime is 11403131420027. The next prime is 11403131420059. The reversal of 11403131420032 is 23002413130411.
It is a tau number, because it is divible by the number of its divisors (64).
It is a junction number, because it is equal to n+sod(n) for n = 11403131419979 and 11403131420006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1613833 + ... + 5040904.
Almost surely, 211403131420032 is an apocalyptic number.
It is an amenable number.
11403131420032 is an abundant number, since it is smaller than the sum of its proper divisors (13399609485008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11403131420032 is a wasteful number, since it uses less digits than its factorization.
11403131420032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6655979 (or 6655967 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11403131420032 its reverse (23002413130411), we get a palindrome (34405544550443).
The spelling of 11403131420032 in words is "eleven trillion, four hundred three billion, one hundred thirty-one million, four hundred twenty thousand, thirty-two".
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