Base | Representation |
---|---|
bin | 10101010000001101… |
… | …00011100010111111 |
3 | 1002110012100111121122 |
4 | 22220012203202333 |
5 | 141332004202333 |
6 | 5124120421155 |
7 | 552520213046 |
oct | 125006434277 |
9 | 32405314548 |
10 | 11410225343 |
11 | 4925858200 |
12 | 22653177bb |
13 | 10cac0923a |
14 | 7a357755d |
15 | 46bac2798 |
hex | 2a81a38bf |
11410225343 has 6 divisors (see below), whose sum is σ = 12541818072. Its totient is φ = 10372932020.
The previous prime is 11410225283. The next prime is 11410225349. The reversal of 11410225343 is 34352201411.
It is a happy number.
11410225343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11410225343 - 212 = 11410221247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11410225349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 47149571 + ... + 47149812.
It is an arithmetic number, because the mean of its divisors is an integer number (2090303012).
Almost surely, 211410225343 is an apocalyptic number.
11410225343 is a deficient number, since it is larger than the sum of its proper divisors (1131592729).
11410225343 is an equidigital number, since it uses as much as digits as its factorization.
11410225343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94299405 (or 94299394 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 11410225343 its reverse (34352201411), we get a palindrome (45762426754).
The spelling of 11410225343 in words is "eleven billion, four hundred ten million, two hundred twenty-five thousand, three hundred forty-three".
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