11413243044 has 72 divisors (see below), whose sum is σ = 33023023488. Its totient is φ = 3255840000.

The previous prime is 11413243007. The next prime is 11413243081. The reversal of 11413243044 is 44034231411.

11413243044 is a `hidden beast` number, since 1 + 1 + 413 + 243 + 0 + 4 + 4 = 666.

It is an interprime number because it is at equal distance from previous prime (11413243007) and next prime (11413243081).

It is a junction number, because it is equal to n+sod(n) for n = 11413242999 and 11413243017.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 128044 + ... + 198044.

It is an arithmetic number, because the mean of its divisors is an integer number (458653104).

Almost surely, 2^11413243044 is an apocalyptic number.

11413243044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11413243044, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16511511744).

11413243044 is an abundant number, since it is smaller than the sum of its proper divisors (21609780444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11413243044 is a wasteful number, since it uses less digits than its factorization.

11413243044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70665 (or 70660 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 11413243044 its reverse (44034231411), we get a palindrome (55447474455).

The spelling of 11413243044 in words is "eleven billion, four hundred thirteen million, two hundred forty-three thousand, forty-four".