Base | Representation |
---|---|
bin | 10101010000101011… |
… | …10011001000010111 |
3 | 1002110110212112002100 |
4 | 22220111303020113 |
5 | 141334020040320 |
6 | 5124342213143 |
7 | 552566165136 |
oct | 125025631027 |
9 | 32413775070 |
10 | 11414221335 |
11 | 4928037480 |
12 | 22667241b3 |
13 | 10cb9a802a |
14 | 7a3cd791d |
15 | 46c111790 |
hex | 2a8573217 |
11414221335 has 24 divisors (see below), whose sum is σ = 21583255824. Its totient is φ = 5534167680.
The previous prime is 11414221333. The next prime is 11414221373. The reversal of 11414221335 is 53312241411.
11414221335 is a `hidden beast` number, since 1 + 1 + 414 + 2 + 213 + 35 = 666.
It is not a de Polignac number, because 11414221335 - 21 = 11414221333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11414221299 and 11414221308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11414221333) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11529022 + ... + 11530011.
It is an arithmetic number, because the mean of its divisors is an integer number (899302326).
Almost surely, 211414221335 is an apocalyptic number.
11414221335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11414221335 is a deficient number, since it is larger than the sum of its proper divisors (10169034489).
11414221335 is a wasteful number, since it uses less digits than its factorization.
11414221335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23059055 (or 23059052 counting only the distinct ones).
The product of its digits is 2880, while the sum is 27.
Adding to 11414221335 its reverse (53312241411), we get a palindrome (64726462746).
The spelling of 11414221335 in words is "eleven billion, four hundred fourteen million, two hundred twenty-one thousand, three hundred thirty-five".
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