Base | Representation |
---|---|
bin | 11001111110011011010100… |
… | …011011100100001111100110 |
3 | 112222111100020222012120201021 |
4 | 121332123110123210033212 |
5 | 104433211240124311032 |
6 | 1042545345544121354 |
7 | 33030435026045455 |
oct | 3176332433441746 |
9 | 488440228176637 |
10 | 114241104135142 |
11 | 33445420030086 |
12 | 1099083676625a |
13 | 4b98b751394ca |
14 | 202d428426b9c |
15 | d31a1752a097 |
hex | 67e6d46e43e6 |
114241104135142 has 64 divisors (see below), whose sum is σ = 186346826968320. Its totient is φ = 52326206208000.
The previous prime is 114241104135113. The next prime is 114241104135163. The reversal of 114241104135142 is 241531401142411.
It is a Harshad number since it is a multiple of its sum of digits (34).
It is a junction number, because it is equal to n+sod(n) for n = 114241104135098 and 114241104135107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 374596563 + ... + 374901409.
It is an arithmetic number, because the mean of its divisors is an integer number (2911669171380).
Almost surely, 2114241104135142 is an apocalyptic number.
114241104135142 is a deficient number, since it is larger than the sum of its proper divisors (72105722833178).
114241104135142 is a wasteful number, since it uses less digits than its factorization.
114241104135142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 306817.
The product of its (nonzero) digits is 15360, while the sum is 34.
Adding to 114241104135142 its reverse (241531401142411), we get a palindrome (355772505277553).
The spelling of 114241104135142 in words is "one hundred fourteen trillion, two hundred forty-one billion, one hundred four million, one hundred thirty-five thousand, one hundred forty-two".
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