Base | Representation |
---|---|
bin | 11001111110101000101110… |
… | …100100110110011101110000 |
3 | 112222112201102100020110012121 |
4 | 121332220232210312131300 |
5 | 104433430231330423100 |
6 | 1043000130332004024 |
7 | 33031454560001164 |
oct | 3176505644663560 |
9 | 488481370213177 |
10 | 114255501420400 |
11 | 33450538a0a63a |
12 | 10993594300614 |
13 | 4b9a32ab49102 |
14 | 202ddd2598ca4 |
15 | d320ab48751a |
hex | 67ea2e936770 |
114255501420400 has 60 divisors (see below), whose sum is σ = 274502585212344. Its totient is φ = 45701577376000.
The previous prime is 114255501420391. The next prime is 114255501420457. The reversal of 114255501420400 is 4024105552411.
It is a super-3 number, since 3×1142555014204003 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27998310 + ... + 31818490.
Almost surely, 2114255501420400 is an apocalyptic number.
114255501420400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
114255501420400 is an abundant number, since it is smaller than the sum of its proper divisors (160247083791944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114255501420400 is a wasteful number, since it uses less digits than its factorization.
114255501420400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3894970 (or 3894959 counting only the distinct ones).
The product of its (nonzero) digits is 32000, while the sum is 34.
Adding to 114255501420400 its reverse (4024105552411), we get a palindrome (118279606972811).
The spelling of 114255501420400 in words is "one hundred fourteen trillion, two hundred fifty-five billion, five hundred one million, four hundred twenty thousand, four hundred".
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