Base | Representation |
---|---|
bin | 10101010010101100… |
… | …10001010001011111 |
3 | 1002111122200011110110 |
4 | 22221112101101133 |
5 | 141402331401030 |
6 | 5130144341103 |
7 | 553162635225 |
oct | 125126212137 |
9 | 32448604413 |
10 | 11431122015 |
11 | 4936630185 |
12 | 2270314793 |
13 | 1102344831 |
14 | 7a6256b15 |
15 | 46d84e1b0 |
hex | 2a959145f |
11431122015 has 16 divisors (see below), whose sum is σ = 19085004288. Its totient is φ = 5831528736.
The previous prime is 11431122007. The next prime is 11431122037. The reversal of 11431122015 is 51022113411.
11431122015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11431122015 - 23 = 11431122007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11431121982 and 11431122000.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16566499 + ... + 16567188.
It is an arithmetic number, because the mean of its divisors is an integer number (1192812768).
Almost surely, 211431122015 is an apocalyptic number.
11431122015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11431122015 is a deficient number, since it is larger than the sum of its proper divisors (7653882273).
11431122015 is a wasteful number, since it uses less digits than its factorization.
11431122015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33133718.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 11431122015 its reverse (51022113411), we get a palindrome (62453235426).
The spelling of 11431122015 in words is "eleven billion, four hundred thirty-one million, one hundred twenty-two thousand, fifteen".
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