1143312100 has 54 divisors (see below), whose sum is σ = 2886058770. Its totient is φ = 391991040.

The previous prime is 1143312091. The next prime is 1143312109. The reversal of 1143312100 is 12133411.

1143312100 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (1143312091) and next prime (1143312109).

It can be written as a sum of positive squares in 3 ways, for example, as 17172736 + 1126139364 = 4144^2 + 33558^2 .

It is not an unprimeable number, because it can be changed into a prime (1143312109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 111765 + ... + 121564.

Almost surely, 2^1143312100 is an apocalyptic number.

1143312100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1143312100 is an abundant number, since it is smaller than the sum of its proper divisors (1742746670).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1143312100 is a wasteful number, since it uses less digits than its factorization.

1143312100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 233357 (or 233343 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1143312100 is about 33812.8984264881. The cubic root of 1143312100 is about 1045.6546343497.

Adding to 1143312100 its reverse (12133411), we get a palindrome (1155445511).

Subtracting from 1143312100 its reverse (12133411), we obtain a square (1131178689 = 33633²).

The spelling of 1143312100 in words is "one billion, one hundred forty-three million, three hundred twelve thousand, one hundred".