Base | Representation |
---|---|
bin | 11001111111111110101000… |
… | …100100110001010111111011 |
3 | 112222212112111210011111000120 |
4 | 121333332220210301113323 |
5 | 104441433134042024430 |
6 | 1043110343331104323 |
7 | 33041231441345100 |
oct | 3177765044612773 |
9 | 488775453144016 |
10 | 114347742533115 |
11 | 334866726908a3 |
12 | 109a94377420a3 |
13 | 4ba5c3b065b90 |
14 | 2034662d96aa7 |
15 | d346a9452610 |
hex | 67ffa89315fb |
114347742533115 has 96 divisors (see below), whose sum is σ = 241261171441920. Its totient is φ = 45712642864896.
The previous prime is 114347742533111. The next prime is 114347742533131. The reversal of 114347742533115 is 511335247743411.
It is not a de Polignac number, because 114347742533115 - 22 = 114347742533111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (114347742533111) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 314747929 + ... + 315111018.
It is an arithmetic number, because the mean of its divisors is an integer number (2513137202520).
Almost surely, 2114347742533115 is an apocalyptic number.
114347742533115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114347742533115 is an abundant number, since it is smaller than the sum of its proper divisors (126913428908805).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114347742533115 is a wasteful number, since it uses less digits than its factorization.
114347742533115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 629859001 (or 629858994 counting only the distinct ones).
The product of its digits is 4233600, while the sum is 51.
The spelling of 114347742533115 in words is "one hundred fourteen trillion, three hundred forty-seven billion, seven hundred forty-two million, five hundred thirty-three thousand, one hundred fifteen".
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