114404504053125 has 432 divisors, whose sum is σ = 235462352569920. Its totient is φ = 48971894400000.

The previous prime is 114404504053121. The next prime is 114404504053141. The reversal of 114404504053125 is 521350405404411.

It is not a de Polignac number, because 114404504053125 - 2² = 114404504053121 is a prime.

It is a super-3 number, since 3×114404504053125³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114404504053121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 431 ways as a sum of consecutive naturals, for example, 9219471921 + ... + 9219484329.

It is an arithmetic number, because the mean of its divisors is an integer number (545051742060).

Almost surely, 2^{114404504053125} is an apocalyptic number.

114404504053125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

114404504053125 is an abundant number, since it is smaller than the sum of its proper divisors (121057848516795).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114404504053125 is a wasteful number, since it uses less digits than its factorization.

114404504053125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12520 (or 12464 counting only the distinct ones).

The product of its (nonzero) digits is 192000, while the sum is 39.

Adding to 114404504053125 its reverse (521350405404411), we get a palindrome (635754909457536).

The spelling of 114404504053125 in words is "one hundred fourteen trillion, four hundred four billion, five hundred four million, fifty-three thousand, one hundred twenty-five".