1144330000063 has 4 divisors (see below), whose sum is σ = 1144333561840. Its totient is φ = 1144326438288.

The previous prime is 1144330000061. The next prime is 1144330000091. The reversal of 1144330000063 is 3600000334411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1144330000063 - 2¹ = 1144330000061 is a prime.

It is a super-2 number, since 2×1144330000063² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1144329999992 and 1144330000037.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1144330000061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1245270 + ... + 1959427.

It is an arithmetic number, because the mean of its divisors is an integer number (286083390460).

Almost surely, 2^{1144330000063} is an apocalyptic number.

1144330000063 is a deficient number, since it is larger than the sum of its proper divisors (3561777).

1144330000063 is an equidigital number, since it uses as much as digits as its factorization.

1144330000063 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3561776.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1144330000063 its reverse (3600000334411), we get a palindrome (4744330334474).

The spelling of 1144330000063 in words is "one trillion, one hundred forty-four billion, three hundred thirty million, sixty-three", and thus it is an aban number.