11503351300 has 72 divisors (see below), whose sum is σ = 28720036800. Its totient is φ = 3917500800.

The previous prime is 11503351253. The next prime is 11503351309. The reversal of 11503351300 is 315330511.

It is a super-2 number, since 2×11503351300² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11503351309) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 49155 + ... + 159445.

It is an arithmetic number, because the mean of its divisors is an integer number (398889400).

Almost surely, 2^11503351300 is an apocalyptic number.

11503351300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11503351300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14360018400).

11503351300 is an abundant number, since it is smaller than the sum of its proper divisors (17216685500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11503351300 is a wasteful number, since it uses less digits than its factorization.

11503351300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110461 (or 110454 counting only the distinct ones).

The product of its (nonzero) digits is 675, while the sum is 22.

Adding to 11503351300 its reverse (315330511), we get a palindrome (11818681811).

The spelling of 11503351300 in words is "eleven billion, five hundred three million, three hundred fifty-one thousand, three hundred".