Base | Representation |
---|---|
bin | 1010011101111111010010… |
… | …1101110111011001000111 |
3 | 1111202101011012111200001011 |
4 | 2213133310231313121013 |
5 | 3002041120200100210 |
6 | 40251434105343051 |
7 | 2265410351425564 |
oct | 247376455673107 |
9 | 44671135450034 |
10 | 11510323050055 |
11 | 3738556319735 |
12 | 135a93ba97a87 |
13 | 65655a16a86b |
14 | 2bb1617b186b |
15 | 14e62370dd8a |
hex | a77f4b77647 |
11510323050055 has 8 divisors (see below), whose sum is σ = 13949143974144. Its totient is φ = 9117087564000.
The previous prime is 11510323050001. The next prime is 11510323050059. The reversal of 11510323050055 is 55005032301511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11510323050055 - 221 = 11510320952903 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11510323049999 and 11510323050026.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11510323050059) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11396358951 + ... + 11396359960.
It is an arithmetic number, because the mean of its divisors is an integer number (1743642996768).
Almost surely, 211510323050055 is an apocalyptic number.
11510323050055 is a deficient number, since it is larger than the sum of its proper divisors (2438820924089).
11510323050055 is a wasteful number, since it uses less digits than its factorization.
11510323050055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22792719017.
The product of its (nonzero) digits is 11250, while the sum is 31.
Adding to 11510323050055 its reverse (55005032301511), we get a palindrome (66515355351566).
The spelling of 11510323050055 in words is "eleven trillion, five hundred ten billion, three hundred twenty-three million, fifty thousand, fifty-five".
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