Base | Representation |
---|---|
bin | 10101011100001110… |
… | …11110011110010000 |
3 | 1002201020012222210011 |
4 | 22232013132132100 |
5 | 142033322130000 |
6 | 5142123244304 |
7 | 555153663526 |
oct | 125607363620 |
9 | 32636188704 |
10 | 11511130000 |
11 | 4977807387 |
12 | 2293079694 |
13 | 1115aa8736 |
14 | 7b2b22316 |
15 | 4758a52ba |
hex | 2ae1de790 |
11511130000 has 50 divisors (see below), whose sum is σ = 27869621054. Its totient is φ = 4604448000.
The previous prime is 11511129967. The next prime is 11511130063. The reversal of 11511130000 is 3111511.
It can be written as a sum of positive squares in 5 ways, for example, as 7216162704 + 4294967296 = 84948^2 + 65536^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is a super-2 number, since 2×115111300002 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 565557 + ... + 585556.
Almost surely, 211511130000 is an apocalyptic number.
11511130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11511130000 is an abundant number, since it is smaller than the sum of its proper divisors (16358491054).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11511130000 is an equidigital number, since it uses as much as digits as its factorization.
11511130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1151141 (or 1151120 counting only the distinct ones).
The product of its (nonzero) digits is 15, while the sum is 13.
Adding to 11511130000 its reverse (3111511), we get a palindrome (11514241511).
The spelling of 11511130000 in words is "eleven billion, five hundred eleven million, one hundred thirty thousand".
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