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11525534130030 = 235384184471001
BaseRepresentation
bin1010011110110111111101…
…0111100001111101101110
31111210211102021211121000120
42213231333113201331232
53002313243214130110
640302431323505410
72266456323450534
oct247557727417556
944724367747016
1011525534130030
113743a51601208
121361886088266
13657b126501bb
142bbba5a60154
1514ec13d1a870
hexa7b7f5e1f6e

11525534130030 has 16 divisors (see below), whose sum is σ = 27661281912144. Its totient is φ = 3073475768000.

The previous prime is 11525534130023. The next prime is 11525534130109. The reversal of 11525534130030 is 3003143552511.

It is a junction number, because it is equal to n+sod(n) for n = 11525534129973 and 11525534130000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 192092235471 + ... + 192092235530.

It is an arithmetic number, because the mean of its divisors is an integer number (1728830119509).

Almost surely, 211525534130030 is an apocalyptic number.

11525534130030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11525534130030 is an abundant number, since it is smaller than the sum of its proper divisors (16135747782114).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11525534130030 is a wasteful number, since it uses less digits than its factorization.

11525534130030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 384184471011.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 11525534130030 its reverse (3003143552511), we get a palindrome (14528677682541).

The spelling of 11525534130030 in words is "eleven trillion, five hundred twenty-five billion, five hundred thirty-four million, one hundred thirty thousand, thirty".

Divisors: 1 2 3 5 6 10 15 30 384184471001 768368942002 1152553413003 1920922355005 2305106826006 3841844710010 5762767065015 11525534130030