Base | Representation |
---|---|
bin | 10101011110111111… |
… | …00010001110100111 |
3 | 1002202211122210011011 |
4 | 22233133202032213 |
5 | 142110224322210 |
6 | 5144310123051 |
7 | 555554126140 |
oct | 125737421647 |
9 | 32684583134 |
10 | 11534214055 |
11 | 4989843811 |
12 | 229a950487 |
13 | 111a7cb840 |
14 | 7b5c10ac7 |
15 | 477914d8a |
hex | 2af7e23a7 |
11534214055 has 64 divisors (see below), whose sum is σ = 17559779328. Its totient is φ = 7077404160.
The previous prime is 11534214053. The next prime is 11534214067. The reversal of 11534214055 is 55041243511.
It is not a de Polignac number, because 11534214055 - 21 = 11534214053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11534214053) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5234584 + ... + 5236786.
It is an arithmetic number, because the mean of its divisors is an integer number (274371552).
Almost surely, 211534214055 is an apocalyptic number.
11534214055 is a deficient number, since it is larger than the sum of its proper divisors (6025565273).
11534214055 is a wasteful number, since it uses less digits than its factorization.
11534214055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2576.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 11534214055 its reverse (55041243511), we get a palindrome (66575457566).
The spelling of 11534214055 in words is "eleven billion, five hundred thirty-four million, two hundred fourteen thousand, fifty-five".
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