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115401414055 = 5236714977471
BaseRepresentation
bin110101101111001110…
…1011101010110100111
3102000212112010020111111
41223132131131112213
53342320230222210
6125003100445451
711223516556204
oct1533635352647
9360775106444
10115401414055
1144a3a0a9474
121a447849887
13ab615738b5
14582a6d6cab
1530063e188a
hex1ade75d5a7

115401414055 has 16 divisors (see below), whose sum is σ = 146659405824. Its totient is φ = 86989145760.

The previous prime is 115401414053. The next prime is 115401414061. The reversal of 115401414055 is 550414104511.

It is not a de Polignac number, because 115401414055 - 21 = 115401414053 is a prime.

It is a super-3 number, since 3×1154014140553 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115401414053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7481031 + ... + 7496440.

It is an arithmetic number, because the mean of its divisors is an integer number (9166212864).

Almost surely, 2115401414055 is an apocalyptic number.

115401414055 is a deficient number, since it is larger than the sum of its proper divisors (31257991769).

115401414055 is a wasteful number, since it uses less digits than its factorization.

115401414055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14977566.

The product of its (nonzero) digits is 8000, while the sum is 31.

Adding to 115401414055 its reverse (550414104511), we get a palindrome (665815518566).

The spelling of 115401414055 in words is "one hundred fifteen billion, four hundred one million, four hundred fourteen thousand, fifty-five".

Divisors: 1 5 23 67 115 335 1541 7705 14977471 74887355 344481833 1003490557 1722409165 5017452785 23080282811 115401414055