11711642140 has 48 divisors (see below), whose sum is σ = 27336566880. Its totient is φ = 4178420480.

The previous prime is 11711642119. The next prime is 11711642177. The reversal of 11711642140 is 4124611711.

It is a super-3 number, since 3×11711642140³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11711642099 and 11711642108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 490555 + ... + 513874.

It is an arithmetic number, because the mean of its divisors is an integer number (569511810).

Almost surely, 2^11711642140 is an apocalyptic number.

11711642140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11711642140 is an abundant number, since it is smaller than the sum of its proper divisors (15624924740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11711642140 is a wasteful number, since it uses less digits than its factorization.

11711642140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1004502 (or 1004500 counting only the distinct ones).

The product of its (nonzero) digits is 1344, while the sum is 28.

The spelling of 11711642140 in words is "eleven billion, seven hundred eleven million, six hundred forty-two thousand, one hundred forty".