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118955840257271 is a prime number
BaseRepresentation
bin11011000011000010010000…
…100110100011110011110111
3120121012001211001000020200102
4123003002100212203303313
5111042433030101213041
61100555320353504315
734025163420622403
oct3303022046436367
9517161731006612
10118955840257271
11349a298571aa76
121141253227209b
13514b645359864
1421536c9c02103
15db44ab12b09b
hex6c30909a3cf7

118955840257271 has 2 divisors, whose sum is σ = 118955840257272. Its totient is φ = 118955840257270.

The previous prime is 118955840257159. The next prime is 118955840257273. The reversal of 118955840257271 is 172752048559811.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-118955840257271 is a prime.

Together with 118955840257273, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 118955840257198 and 118955840257207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (118955840257273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59477920128635 + 59477920128636.

It is an arithmetic number, because the mean of its divisors is an integer number (59477920128636).

Almost surely, 2118955840257271 is an apocalyptic number.

118955840257271 is a deficient number, since it is larger than the sum of its proper divisors (1).

118955840257271 is an equidigital number, since it uses as much as digits as its factorization.

118955840257271 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56448000, while the sum is 65.

The spelling of 118955840257271 in words is "one hundred eighteen trillion, nine hundred fifty-five billion, eight hundred forty million, two hundred fifty-seven thousand, two hundred seventy-one".