Base | Representation |
---|---|
bin | 10110010100011111… |
… | …10000011001110000 |
3 | 1010221010020122122211 |
4 | 23022033300121300 |
5 | 144020131001030 |
6 | 5301022341504 |
7 | 602644231453 |
oct | 131217603160 |
9 | 33833218584 |
10 | 11983062640 |
11 | 509a14335a |
12 | 23a512a894 |
13 | 118c7b4413 |
14 | 81968d49a |
15 | 4a202712a |
hex | 2ca3f0670 |
11983062640 has 40 divisors (see below), whose sum is σ = 27888750720. Its totient is φ = 4788385536.
The previous prime is 11983062601. The next prime is 11983062643. The reversal of 11983062640 is 4626038911.
It is a tau number, because it is divible by the number of its divisors (40).
It is a Harshad number since it is a multiple of its sum of digits (40).
It is a junction number, because it is equal to n+sod(n) for n = 11983062593 and 11983062602.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11983062643) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4641 + ... + 154879.
It is an arithmetic number, because the mean of its divisors is an integer number (697218768).
Almost surely, 211983062640 is an apocalyptic number.
11983062640 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11983062640 is an abundant number, since it is smaller than the sum of its proper divisors (15905688080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11983062640 is a wasteful number, since it uses less digits than its factorization.
11983062640 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151249 (or 151243 counting only the distinct ones).
The product of its (nonzero) digits is 62208, while the sum is 40.
The spelling of 11983062640 in words is "eleven billion, nine hundred eighty-three million, sixty-two thousand, six hundred forty".
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