12000131111 has 2 divisors, whose sum is σ = 12000131112. Its totient is φ = 12000131110.

The previous prime is 12000131083. The next prime is 12000131137. The reversal of 12000131111 is 11113100021.

It is a happy number.

12000131111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12000131111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12000131092 and 12000131101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000191111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000065555 + 6000065556.

It is an arithmetic number, because the mean of its divisors is an integer number (6000065556).

Almost surely, 2^12000131111 is an apocalyptic number.

12000131111 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000131111 is an equidigital number, since it uses as much as digits as its factorization.

12000131111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 12000131111 its reverse (11113100021), we get a palindrome (23113231132).

The spelling of 12000131111 in words is "twelve billion, one hundred thirty-one thousand, one hundred eleven".