1200013130000 has 50 divisors (see below), whose sum is σ = 2905351813254. Its totient is φ = 480005248000.

The previous prime is 1200013129993. The next prime is 1200013130021. The reversal of 1200013130000 is 313100021.

It can be written as a sum of positive squares in 5 ways, for example, as 427632292096 + 772380837904 = 653936^2 + 878852^2 .

It is a tau number, because it is divible by the number of its divisors (50).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 59990657 + ... + 60010656.

Almost surely, 2^{1200013130000} is an apocalyptic number.

1200013130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1200013130000 is an abundant number, since it is smaller than the sum of its proper divisors (1705338683254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1200013130000 is an equidigital number, since it uses as much as digits as its factorization.

1200013130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120001341 (or 120001320 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 1200013130000 its reverse (313100021), we get a palindrome (1200326230021).

The spelling of 1200013130000 in words is "one trillion, two hundred billion, thirteen million, one hundred thirty thousand".