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12001101132020 = 2257111323611912237
BaseRepresentation
bin1010111010100011100101…
…0111101011000011110100
31120111021221101001101221212
42232220321113223003310
53033111223342211040
641305121343100552
72346023321331650
oct256507127530364
946437841041855
1012001101132020
1139077027a2670
121419a885a1758
136909118788b0
142d6bdbd33a60
1515c29992bd65
hexaea395eb0f4

12001101132020 has 768 divisors, whose sum is σ = 36092153954304. Its totient is φ = 3230143488000.

The previous prime is 12001101131947. The next prime is 12001101132029. The reversal of 12001101132020 is 2023110110021.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 12001101131986 and 12001101132004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12001101132029) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 5364818342 + ... + 5364820578.

It is an arithmetic number, because the mean of its divisors is an integer number (46994992128).

Almost surely, 212001101132020 is an apocalyptic number.

12001101132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12001101132020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18046076977152).

12001101132020 is an abundant number, since it is smaller than the sum of its proper divisors (24091052822284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12001101132020 is a wasteful number, since it uses less digits than its factorization.

12001101132020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2552 (or 2550 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 12001101132020 its reverse (2023110110021), we get a palindrome (14024211242041).

It can be divided in two parts, 12001101 and 132020, that added together give a palindrome (12133121).

The spelling of 12001101132020 in words is "twelve trillion, one billion, one hundred one million, one hundred thirty-two thousand, twenty".