12011031310000 has 100 divisors (see below), whose sum is σ = 29082848790600. Its totient is φ = 4803926656000.

The previous prime is 12011031309941. The next prime is 12011031310001. The reversal of 12011031310000 is 1313011021.

It is a tau number, because it is divible by the number of its divisors (100).

It is a super-2 number, since 2×12011031310000² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12011031310001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 108534696 + ... + 108645304.

It is an arithmetic number, because the mean of its divisors is an integer number (290828487906).

Almost surely, 2^{12011031310000} is an apocalyptic number.

12011031310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12011031310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14541424395300).

12011031310000 is an abundant number, since it is smaller than the sum of its proper divisors (17071817480600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12011031310000 is a wasteful number, since it uses less digits than its factorization.

12011031310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121496 (or 121475 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 12011031310000 its reverse (1313011021), we get a palindrome (12012344321021).

The spelling of 12011031310000 in words is "twelve trillion, eleven billion, thirty-one million, three hundred ten thousand".