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1201210211120 = 245139115193851
BaseRepresentation
bin10001011110101101101…
…101010011101100110000
311020211112101221012112112
4101132231231103230300
5124140034303223440
62315454531344452
7152533052220233
oct21365555235460
94224471835475
101201210211120
11423480937677
12174976a52128
1389373245b6a
14421d315541a
15213a6091965
hex117adb53b30

1201210211120 has 80 divisors (see below), whose sum is σ = 2815379804160. Its totient is φ = 476607840000.

The previous prime is 1201210211099. The next prime is 1201210211141. The reversal of 1201210211120 is 211120121021.

It is an interprime number because it is at equal distance from previous prime (1201210211099) and next prime (1201210211141).

It is a tau number, because it is divible by the number of its divisors (80).

It is a junction number, because it is equal to n+sod(n) for n = 1201210211095 and 1201210211104.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12752195 + ... + 12846045.

It is an arithmetic number, because the mean of its divisors is an integer number (35192247552).

Almost surely, 21201210211120 is an apocalyptic number.

1201210211120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1201210211120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1407689902080).

1201210211120 is an abundant number, since it is smaller than the sum of its proper divisors (1614169593040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1201210211120 is a wasteful number, since it uses less digits than its factorization.

1201210211120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95154 (or 95148 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 1201210211120 its reverse (211120121021), we get a palindrome (1412330332141).

Subtracting from 1201210211120 its reverse (211120121021), we obtain a palindrome (990090090099).

The spelling of 1201210211120 in words is "one trillion, two hundred one billion, two hundred ten million, two hundred eleven thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 40 80 139 278 556 695 1112 1151 1390 2224 2302 2780 4604 5560 5755 9208 11120 11510 18416 23020 46040 92080 93851 159989 187702 319978 375404 469255 639956 750808 799945 938510 1279912 1501616 1599890 1877020 2559824 3199780 3754040 6399560 7508080 12799120 13045289 26090578 52181156 65226445 104362312 108022501 130452890 208724624 216045002 260905780 432090004 521811560 540112505 864180008 1043623120 1080225010 1728360016 2160450020 4320900040 8641800080 15015127639 30030255278 60060510556 75075638195 120121021112 150151276390 240242042224 300302552780 600605105560 1201210211120