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12012111103200 = 2535213409941329
BaseRepresentation
bin1010111011001100100110…
…0111011000010011100000
31120112100100200020220002020
42232303021213120103200
53033301300420300300
641314142045021440
72346563211464205
oct256631147302340
946470320226066
1012012111103200
1139113426209aa
12142003b854880
13691977884940
142d756427bcac
1515c6e12da8a0
hexaecc99d84e0

12012111103200 has 288 divisors, whose sum is σ = 42210065570400. Its totient is φ = 2949594808320.

The previous prime is 12012111103147. The next prime is 12012111103297. The reversal of 12012111103200 is 230111121021.

It is a super-4 number, since 4×120121111032004 (a number of 53 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 12012111103200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12290136 + ... + 13231464.

It is an arithmetic number, because the mean of its divisors is an integer number (146562727675).

Almost surely, 212012111103200 is an apocalyptic number.

12012111103200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12012111103200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21105032785200).

12012111103200 is an abundant number, since it is smaller than the sum of its proper divisors (30197954467200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12012111103200 is a wasteful number, since it uses less digits than its factorization.

12012111103200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 941774 (or 941761 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 12012111103200 its reverse (230111121021), we get a palindrome (12242222224221).

The spelling of 12012111103200 in words is "twelve trillion, twelve billion, one hundred eleven million, one hundred three thousand, two hundred".