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12012115 = 517141319
BaseRepresentation
bin101101110100…
…101001010011
3211121021112011
4231310221103
511033341430
61105243351
7204046513
oct55645123
924537464
1012012115
116864975
124033557
13264767b
141849843
1510c422a
hexb74a53

12012115 has 8 divisors (see below), whose sum is σ = 15262560. Its totient is φ = 9044352.

The previous prime is 12012113. The next prime is 12012131. The reversal of 12012115 is 51121021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12012115 - 21 = 12012113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012095 and 12012104.

It is not an unprimeable number, because it can be changed into a prime (12012113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70575 + ... + 70744.

It is an arithmetic number, because the mean of its divisors is an integer number (1907820).

Almost surely, 212012115 is an apocalyptic number.

12012115 is a deficient number, since it is larger than the sum of its proper divisors (3250445).

12012115 is a wasteful number, since it uses less digits than its factorization.

12012115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141341.

The product of its (nonzero) digits is 20, while the sum is 13.

The square root of 12012115 is about 3465.8498236363. The cubic root of 12012115 is about 229.0198682253.

Adding to 12012115 its reverse (51121021), we get a palindrome (63133136).

It can be divided in two parts, 1201211 and 5, that added together give a square (1201216 = 10962).

The spelling of 12012115 in words is "twelve million, twelve thousand, one hundred fifteen".

Divisors: 1 5 17 85 141319 706595 2402423 12012115