Base | Representation |
---|---|
bin | 10001011110101101110… |
… | …100100011100111000100 |
3 | 11020211112112111202002120 |
4 | 101132231310203213010 |
5 | 124140040300030200 |
6 | 2315455040205540 |
7 | 152533104323145 |
oct | 21365564434704 |
9 | 4224475452076 |
10 | 1201212111300 |
11 | 423481a15273 |
12 | 1749776098b0 |
13 | 8937375ca26 |
14 | 421d34cbacc |
15 | 213a63199a0 |
hex | 117add239c4 |
1201212111300 has 72 divisors (see below), whose sum is σ = 3482472420000. Its totient is φ = 319681259520.
The previous prime is 1201212111283. The next prime is 1201212111347. The reversal of 1201212111300 is 31112121021.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1201212111300.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3862365 + ... + 4161764.
It is an arithmetic number, because the mean of its divisors is an integer number (48367672500).
Almost surely, 21201212111300 is an apocalyptic number.
1201212111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1201212111300 is an abundant number, since it is smaller than the sum of its proper divisors (2281260308700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201212111300 is a wasteful number, since it uses less digits than its factorization.
1201212111300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8024645 (or 8024638 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1201212111300 its reverse (31112121021), we get a palindrome (1232324232321).
The spelling of 1201212111300 in words is "one trillion, two hundred one billion, two hundred twelve million, one hundred eleven thousand, three hundred".
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