| Base | Representation |
|---|---|
| bin | 100011110011001… |
| … | …0010110111111000 |
| 3 | 10002201022100120211 |
| 4 | 1013212102313320 |
| 5 | 4430003033422 |
| 6 | 315110200504 |
| 7 | 41524132240 |
| oct | 10746226770 |
| 9 | 3081270524 |
| 10 | 1201221112 |
| 11 | 567070223 |
| 12 | 296353134 |
| 13 | 161b31230 |
| 14 | b576ab20 |
| 15 | 706cc577 |
| hex | 47992df8 |
1201221112 has 64 divisors (see below), whose sum is σ = 2831109120. Its totient is φ = 465084288.
The previous prime is 1201221107. The next prime is 1201221127. The reversal of 1201221112 is 2111221021.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a junction number, because it is equal to n+sod(n) for n = 1201221092 and 1201221101.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16663 + ... + 51769.
It is an arithmetic number, because the mean of its divisors is an integer number (44236080).
Almost surely, 21201221112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1201221112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1415554560).
1201221112 is an abundant number, since it is smaller than the sum of its proper divisors (1629888008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201221112 is a wasteful number, since it uses less digits than its factorization.
1201221112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35180 (or 35176 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 13.
The square root of 1201221112 is about 34658.6369033752. The cubic root of 1201221112 is about 1063.0188984126.
Adding to 1201221112 its reverse (2111221021), we get a palindrome (3312442133).
Subtracting 1201221112 from its reverse (2111221021), we obtain a palindrome (909999909).
It can be divided in two parts, 12012 and 21112, that added together give a square (33124 = 1822).
The spelling of 1201221112 in words is "one billion, two hundred one million, two hundred twenty-one thousand, one hundred twelve".
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