Base | Representation |
---|---|
bin | 1010111011001101000000… |
… | …1011011010000101111011 |
3 | 1120112100122100102221121000 |
4 | 2232303100023122011323 |
5 | 3033302012112223003 |
6 | 41314201021020043 |
7 | 2346566016415206 |
oct | 256632013320573 |
9 | 46470570387530 |
10 | 12012221211003 |
11 | 3911399796592 |
12 | 14200706b4623 |
13 | 6919946270a0 |
14 | 2d7574b4093d |
15 | 15c6eacda1a3 |
hex | aecd02da17b |
12012221211003 has 64 divisors (see below), whose sum is σ = 19204224399360. Its totient is φ = 7376936716800.
The previous prime is 12012221210921. The next prime is 12012221211007. The reversal of 12012221211003 is 30011212221021.
It is not a de Polignac number, because 12012221211003 - 222 = 12012217016699 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12012221211007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 855991075 + ... + 856005107.
It is an arithmetic number, because the mean of its divisors is an integer number (300066006240).
Almost surely, 212012221211003 is an apocalyptic number.
12012221211003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12012221211003 is a deficient number, since it is larger than the sum of its proper divisors (7192003188357).
12012221211003 is a wasteful number, since it uses less digits than its factorization.
12012221211003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18897 (or 18891 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 12012221211003 its reverse (30011212221021), we get a palindrome (42023433432024).
The spelling of 12012221211003 in words is "twelve trillion, twelve billion, two hundred twenty-one million, two hundred eleven thousand, three".
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