120130101110015 has 4 divisors (see below), whose sum is σ = 144156121332024. Its totient is φ = 96104080888008.

The previous prime is 120130101109969. The next prime is 120130101110017. The reversal of 120130101110015 is 510011101031021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120130101110015 - 2¹⁶ = 120130101044479 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120130101109975 and 120130101110002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120130101110017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12013010110997 + ... + 12013010111006.

It is an arithmetic number, because the mean of its divisors is an integer number (36039030333006).

Almost surely, 2^{120130101110015} is an apocalyptic number.

120130101110015 is a deficient number, since it is larger than the sum of its proper divisors (24026020222009).

120130101110015 is an equidigital number, since it uses as much as digits as its factorization.

120130101110015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24026020222008.

The product of its (nonzero) digits is 30, while the sum is 17.

Adding to 120130101110015 its reverse (510011101031021), we get a palindrome (630141202141036).

The spelling of 120130101110015 in words is "one hundred twenty trillion, one hundred thirty billion, one hundred one million, one hundred ten thousand, fifteen".