Base | Representation |
---|---|
bin | 11011010100001001000000… |
… | …110110100001000010000100 |
3 | 120202100102221110201222200012 |
4 | 123110021000312201002010 |
5 | 111221212422231131040 |
6 | 1103255322411005352 |
7 | 34206126115632662 |
oct | 3324110066410204 |
9 | 522312843658605 |
10 | 120131323302020 |
11 | 35306454206778 |
12 | 11582309139858 |
13 | 5205448507844 |
14 | 219455c1a3c32 |
15 | dd4d5875d865 |
hex | 6d4240da1084 |
120131323302020 has 48 divisors (see below), whose sum is σ = 252576985038336. Its totient is φ = 47995174656000.
The previous prime is 120131323301963. The next prime is 120131323302043. The reversal of 120131323302020 is 20203323131021.
It is a super-2 number, since 2×1201313233020202 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 107283635 + ... + 108397605.
It is an arithmetic number, because the mean of its divisors is an integer number (5262020521632).
Almost surely, 2120131323302020 is an apocalyptic number.
120131323302020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
120131323302020 is an abundant number, since it is smaller than the sum of its proper divisors (132445661736316).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120131323302020 is a wasteful number, since it uses less digits than its factorization.
120131323302020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1120412 (or 1120410 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 120131323302020 its reverse (20203323131021), we get a palindrome (140334646433041).
The spelling of 120131323302020 in words is "one hundred twenty trillion, one hundred thirty-one billion, three hundred twenty-three million, three hundred two thousand, twenty".
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