Base | Representation |
---|---|
bin | 110111111100010000… |
… | …0001101011000110000 |
3 | 102111002022000110102212 |
4 | 1233320200031120300 |
5 | 3432013111410000 |
6 | 131104413431252 |
7 | 11452005200204 |
oct | 1577040153060 |
9 | 374068013385 |
10 | 120133310000 |
11 | 46a48137980 |
12 | 1b34849b528 |
13 | b4369c1622 |
14 | 5b58d28b04 |
15 | 31d1a39c35 |
hex | 1bf880d630 |
120133310000 has 200 divisors, whose sum is σ = 317921032704. Its totient is φ = 43598880000.
The previous prime is 120133309997. The next prime is 120133310009. The reversal of 120133310000 is 13331021.
It is a tau number, because it is divible by the number of its divisors (200).
It is a super-2 number, since 2×1201333100002 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120133310009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 90529337 + ... + 90530663.
Almost surely, 2120133310000 is an apocalyptic number.
120133310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120133310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158960516352).
120133310000 is an abundant number, since it is smaller than the sum of its proper divisors (197787722704).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120133310000 is a wasteful number, since it uses less digits than its factorization.
120133310000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2189 (or 2168 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 120133310000 its reverse (13331021), we get a palindrome (120146641021).
The spelling of 120133310000 in words is "one hundred twenty billion, one hundred thirty-three million, three hundred ten thousand".
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