Base | Representation |
---|---|
bin | 100011110011011… |
… | …0000111101000000 |
3 | 10002201112121121002 |
4 | 1013212300331000 |
5 | 4430021004240 |
6 | 315112551132 |
7 | 41525154401 |
oct | 10746607500 |
9 | 3081477532 |
10 | 1201344320 |
11 | 567144850 |
12 | 2963b24a8 |
13 | 161b75337 |
14 | b579d9a8 |
15 | 70703d15 |
hex | 479b0f40 |
1201344320 has 112 divisors (see below), whose sum is σ = 3193743168. Its totient is φ = 426639360.
The previous prime is 1201344307. The next prime is 1201344337. The reversal of 1201344320 is 234431021.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 1201344292 and 1201344301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 147392 + ... + 155328.
It is an arithmetic number, because the mean of its divisors is an integer number (28515564).
Almost surely, 21201344320 is an apocalyptic number.
1201344320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1201344320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1596871584).
1201344320 is an abundant number, since it is smaller than the sum of its proper divisors (1992398848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201344320 is a wasteful number, since it uses less digits than its factorization.
1201344320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8008 (or 7998 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
The square root of 1201344320 is about 34660.4143079681. The cubic root of 1201344320 is about 1063.0552414176.
Adding to 1201344320 its reverse (234431021), we get a palindrome (1435775341).
The spelling of 1201344320 in words is "one billion, two hundred one million, three hundred forty-four thousand, three hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •