12014132044037 has 2 divisors, whose sum is σ = 12014132044038. Its totient is φ = 12014132044036.

The previous prime is 12014132044003. The next prime is 12014132044039. The reversal of 12014132044037 is 73044023141021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7744788438916 + 4269343605121 = 2782946^2 + 2066239^2 .

It is a cyclic number.

It is not a de Polignac number, because 12014132044037 - 2¹² = 12014132039941 is a prime.

Together with 12014132044039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12014132043994 and 12014132044012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12014132044039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007066022018 + 6007066022019.

It is an arithmetic number, because the mean of its divisors is an integer number (6007066022019).

Almost surely, 2^{12014132044037} is an apocalyptic number.

It is an amenable number.

12014132044037 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014132044037 is an equidigital number, since it uses as much as digits as its factorization.

12014132044037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 32.

Adding to 12014132044037 its reverse (73044023141021), we get a palindrome (85058155185058).

The spelling of 12014132044037 in words is "twelve trillion, fourteen billion, one hundred thirty-two million, forty-four thousand, thirty-seven".