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12021201220120 = 23531831087107453
BaseRepresentation
bin1010111011101110011101…
…1011011011001000011000
31120120012211011220200021021
42232323213123123020120
53033423410003020440
641322244045452224
72350334400265621
oct256734733331030
946505734820237
1012021201220120
113915187773324
121421957b71074
13692795bc8151
142d7b87630a48
1515ca7436884a
hexaeee76db218

12021201220120 has 128 divisors (see below), whose sum is σ = 28282855587840. Its totient is φ = 4593031441920.

The previous prime is 12021201220109. The next prime is 12021201220207. The reversal of 12021201220120 is 2102210212021.

It is a happy number.

It is a super-3 number, since 3×120212012201203 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12021201220094 and 12021201220103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 111820314 + ... + 111927766.

It is an arithmetic number, because the mean of its divisors is an integer number (220959809280).

Almost surely, 212021201220120 is an apocalyptic number.

12021201220120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12021201220120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14141427793920).

12021201220120 is an abundant number, since it is smaller than the sum of its proper divisors (16261654367720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12021201220120 is a wasteful number, since it uses less digits than its factorization.

12021201220120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108665 (or 108661 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 12021201220120 its reverse (2102210212021), we get a palindrome (14123411432141).

The spelling of 12021201220120 in words is "twelve trillion, twenty-one billion, two hundred one million, two hundred twenty thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 20 31 40 62 83 124 155 166 248 310 332 415 620 664 830 1087 1240 1660 2174 2573 3320 4348 5146 5435 8696 10292 10870 12865 20584 21740 25730 33697 43480 51460 67394 90221 102920 107453 134788 168485 180442 214906 269576 336970 360884 429812 451105 537265 673940 721768 859624 902210 1074530 1347880 1804420 2149060 2796851 3331043 3608840 4298120 5593702 6662086 8918599 11187404 13324172 13984255 16655215 17837198 22374808 26648344 27968510 33310430 35674396 44592995 55937020 66620860 71348792 89185990 111874040 116801411 133241720 178371980 233602822 276476569 356743960 467205644 552953138 584007055 934411288 1105906276 1168014110 1382382845 2211812552 2336028220 2764765690 3620843741 4672056440 5529531380 7241687482 9694517113 11059062760 14483374964 18104218705 19389034226 28966749928 36208437410 38778068452 48472585565 72416874820 77556136904 96945171130 144833749640 193890342260 300530030503 387780684520 601060061006 1202120122012 1502650152515 2404240244024 3005300305030 6010600610060 12021201220120