Base | Representation |
---|---|
bin | 1110010101001… |
… | …10101100010001 |
3 | 22101012211102122 |
4 | 13022212230101 |
5 | 221234023213 |
6 | 15532424025 |
7 | 2656566614 |
oct | 712465421 |
9 | 271184378 |
10 | 120220433 |
11 | 61952433 |
12 | 34318015 |
13 | 1bba3368 |
14 | 11d7617b |
15 | a84ad08 |
hex | 72a6b11 |
120220433 has 2 divisors, whose sum is σ = 120220434. Its totient is φ = 120220432.
The previous prime is 120220427. The next prime is 120220439. The reversal of 120220433 is 334022021.
It is a balanced prime because it is at equal distance from previous prime (120220427) and next prime (120220439).
It can be written as a sum of positive squares in only one way, i.e., 68840209 + 51380224 = 8297^2 + 7168^2 .
It is a cyclic number.
It is not a de Polignac number, because 120220433 - 210 = 120219409 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (120220439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110216 + 60110217.
It is an arithmetic number, because the mean of its divisors is an integer number (60110217).
Almost surely, 2120220433 is an apocalyptic number.
It is an amenable number.
120220433 is a deficient number, since it is larger than the sum of its proper divisors (1).
120220433 is an equidigital number, since it uses as much as digits as its factorization.
120220433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 17.
The square root of 120220433 is about 10964.5078776934. The cubic root of 120220433 is about 493.5442493053.
Adding to 120220433 its reverse (334022021), we get a palindrome (454242454).
The spelling of 120220433 in words is "one hundred twenty million, two hundred twenty thousand, four hundred thirty-three".
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