Base | Representation |
---|---|
bin | 11011011000000111001111… |
… | …101110010011100101000100 |
3 | 120210022112112220122012112022 |
4 | 123120013033232103211010 |
5 | 111240201003111400200 |
6 | 1104024550122142312 |
7 | 34234631610020054 |
oct | 3330071756234504 |
9 | 523275486565468 |
10 | 120404303231300 |
11 | 354011a6270a10 |
12 | 116071b1651998 |
13 | 522510044920a |
14 | 21a385695b564 |
15 | ddbed3c20885 |
hex | 6d81cfb93944 |
120404303231300 has 72 divisors (see below), whose sum is σ = 285046500335520. Its totient is φ = 43780821235200.
The previous prime is 120404303231281. The next prime is 120404303231339. The reversal of 120404303231300 is 3132303404021.
It is a super-2 number, since 2×1204043032313002 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120404303231300.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15657071 + ... + 22044329.
Almost surely, 2120404303231300 is an apocalyptic number.
120404303231300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
120404303231300 is an abundant number, since it is smaller than the sum of its proper divisors (164642197104220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120404303231300 is a wasteful number, since it uses less digits than its factorization.
120404303231300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6404421 (or 6404414 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 120404303231300 its reverse (3132303404021), we get a palindrome (123536606635321).
The spelling of 120404303231300 in words is "one hundred twenty trillion, four hundred four billion, three hundred three million, two hundred thirty-one thousand, three hundred".
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