12050117 has 2 divisors, whose sum is σ = 12050118. Its totient is φ = 12050116.

The previous prime is 12050113. The next prime is 12050119. The reversal of 12050117 is 71105021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6522916 + 5527201 = 2554^2 + 2351^2 .

It is a cyclic number.

It is not a de Polignac number, because 12050117 - 2² = 12050113 is a prime.

Together with 12050119, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12050095 and 12050104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12050113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6025058 + 6025059.

It is an arithmetic number, because the mean of its divisors is an integer number (6025059).

Almost surely, 2^12050117 is an apocalyptic number.

It is an amenable number.

12050117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12050117 is an equidigital number, since it uses as much as digits as its factorization.

12050117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70, while the sum is 17.

The square root of 12050117 is about 3471.3278439237. The cubic root of 12050117 is about 229.2611260772.

Adding to 12050117 its reverse (71105021), we get a palindrome (83155138).

It can be divided in two parts, 12050 and 117, that added together give a cube (12167 = 23³).

The spelling of 12050117 in words is "twelve million, fifty thousand, one hundred seventeen".