Search a number
-
+
12052241300 = 22521122414133
BaseRepresentation
bin10110011100101111…
…01001101110010100
31011002221102021221102
423032113221232110
5144140333210200
65311533205232
7604444234511
oct131627515624
934087367842
1012052241300
1151251a3300
122404330818
1311a0c26138
1482493a308
154a813e6d5
hex2ce5e9b94

12052241300 has 108 divisors (see below), whose sum is σ = 28873352508. Its totient is φ = 4363392000.

The previous prime is 12052241263. The next prime is 12052241309. The reversal of 12052241300 is 314225021.

It can be written as a sum of positive squares in 6 ways, for example, as 159466384 + 11892774916 = 12628^2 + 109054^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12052241309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 2914034 + ... + 2918166.

Almost surely, 212052241300 is an apocalyptic number.

12052241300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12052241300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14436676254).

12052241300 is an abundant number, since it is smaller than the sum of its proper divisors (16821111208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12052241300 is a wasteful number, since it uses less digits than its factorization.

12052241300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4410 (or 4392 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 20.

Adding to 12052241300 its reverse (314225021), we get a palindrome (12366466321).

It can be divided in two parts, 12052 and 241300, that added together give a palindrome (253352).

The spelling of 12052241300 in words is "twelve billion, fifty-two million, two hundred forty-one thousand, three hundred".

Divisors: 1 2 4 5 10 11 20 22 25 44 50 55 100 110 121 220 241 242 275 482 484 550 605 964 1100 1205 1210 2410 2420 2651 3025 4133 4820 5302 6025 6050 8266 10604 12050 12100 13255 16532 20665 24100 26510 29161 41330 45463 53020 58322 66275 82660 90926 103325 116644 132550 145805 181852 206650 227315 265100 291610 413300 454630 500093 583220 729025 909260 996053 1000186 1136575 1458050 1992106 2000372 2273150 2500465 2916100 3984212 4546300 4980265 5000930 9960530 10001860 10956583 12502325 19921060 21913166 24901325 25004650 43826332 49802650 50009300 54782915 99605300 109565830 120522413 219131660 241044826 273914575 482089652 547829150 602612065 1095658300 1205224130 2410448260 3013060325 6026120650 12052241300