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121101010310000 = 245473139254003
BaseRepresentation
bin11011100010010000000110…
…101100111001001101110000
3120212210010212121220212110002
4123202100012230321031300
5111333104332114410000
61105321011444525132
734336154633333000
oct3342200654711560
9525703777825402
10121101010310000
113564a717250046
12116ba22b3b07a8
135275a12611ac6
1421c946a7aa000
15e001adb728d5
hex6e2406b39370

121101010310000 has 400 divisors, whose sum is σ = 344382687264000. Its totient is φ = 41221476576000.

The previous prime is 121101010309991. The next prime is 121101010310023. The reversal of 121101010310000 is 13010101121.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×1211010103100002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 476642999 + ... + 476897001.

It is an arithmetic number, because the mean of its divisors is an integer number (860956718160).

Almost surely, 2121101010310000 is an apocalyptic number.

121101010310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121101010310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172191343632000).

121101010310000 is an abundant number, since it is smaller than the sum of its proper divisors (223281676954000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121101010310000 is an equidigital number, since it uses as much as digits as its factorization.

121101010310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254191 (or 254156 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 121101010310000 its reverse (13010101121), we get a palindrome (121114020411121).

The spelling of 121101010310000 in words is "one hundred twenty-one trillion, one hundred one billion, ten million, three hundred ten thousand".