Base | Representation |
---|---|
bin | 11011100010010001001110… |
… | …111011111001000110000100 |
3 | 120212210021000002022022200002 |
4 | 123202101032323321012010 |
5 | 111333114322340414340 |
6 | 1105321332015540432 |
7 | 34336226650255361 |
oct | 3342211673710604 |
9 | 525707002268602 |
10 | 121102222201220 |
11 | 35650189338937 |
12 | 116ba50922a718 |
13 | 5275b7670a8c0 |
14 | 21c9543713468 |
15 | e0023025b715 |
hex | 6e244eef9184 |
121102222201220 has 48 divisors (see below), whose sum is σ = 273922434392880. Its totient is φ = 44707303213056.
The previous prime is 121102222201127. The next prime is 121102222201241. The reversal of 121102222201220 is 22102222201121.
It can be written as a sum of positive squares in 8 ways, for example, as 18542204396356 + 102560017804864 = 4306066^2 + 10127192^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 121102222201192 and 121102222201201.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36769265 + ... + 39927224.
It is an arithmetic number, because the mean of its divisors is an integer number (5706717383185).
Almost surely, 2121102222201220 is an apocalyptic number.
121102222201220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121102222201220 is an abundant number, since it is smaller than the sum of its proper divisors (152820212191660).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121102222201220 is a wasteful number, since it uses less digits than its factorization.
121102222201220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76702584 (or 76702582 counting only the distinct ones).
The product of its (nonzero) digits is 256, while the sum is 20.
Adding to 121102222201220 its reverse (22102222201121), we get a palindrome (143204444402341).
Subtracting from 121102222201220 its reverse (22102222201121), we obtain a palindrome (99000000000099).
The spelling of 121102222201220 in words is "one hundred twenty-one trillion, one hundred two billion, two hundred twenty-two million, two hundred one thousand, two hundred twenty".
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