121103132011020 has 72 divisors (see below), whose sum is σ = 367799122126800. Its totient is φ = 32254348314240.

The previous prime is 121103132010877. The next prime is 121103132011051. The reversal of 121103132011020 is 20110231301121.

121103132011020 is a `hidden beast` number, since 1 + 211 + 0 + 3 + 1 + 320 + 110 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 121103132010984 and 121103132011002.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 414647595 + ... + 414939554.

It is an arithmetic number, because the mean of its divisors is an integer number (5108321140650).

Almost surely, 2^{121103132011020} is an apocalyptic number.

121103132011020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

121103132011020 is an abundant number, since it is smaller than the sum of its proper divisors (246695990115780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121103132011020 is a wasteful number, since it uses less digits than its factorization.

121103132011020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 829587975 (or 829587970 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 121103132011020 its reverse (20110231301121), we get a palindrome (141213363312141).

The spelling of 121103132011020 in words is "one hundred twenty-one trillion, one hundred three billion, one hundred thirty-two million, eleven thousand, twenty".