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12111213312 = 28351121609
BaseRepresentation
bin10110100011110001…
…00111001100000000
31011021001101101100000
423101320213030000
5144300432311222
65321441200000
7606061420542
oct132170471400
934231341300
1012111213312
115155511900
122420030000
1311b0203213
1482c6cb692
154ad3dc9ac
hex2d1e27300

12111213312 has 324 divisors, whose sum is σ = 39829036520. Its totient is φ = 3667783680.

The previous prime is 12111213281. The next prime is 12111213319. The reversal of 12111213312 is 21331211121.

12111213312 is a `hidden beast` number, since 1 + 211 + 121 + 331 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (324).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a nude number because it is divisible by every one of its digits and also a Zuckerman number because it is divisible by the product of its digits.

It is an insolite number, because it is divisible by the sum (36) and by the product (5184) of the squares of its digits.

It is not an unprimeable number, because it can be changed into a prime (12111213319) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 7526364 + ... + 7527972.

Almost surely, 212111213312 is an apocalyptic number.

12111213312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12111213312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19914518260).

12111213312 is an abundant number, since it is smaller than the sum of its proper divisors (27717823208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12111213312 is an equidigital number, since it uses as much as digits as its factorization.

12111213312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1662 (or 1625 counting only the distinct ones).

The product of its digits is 72, while the sum is 18.

Adding to 12111213312 its reverse (21331211121), we get a palindrome (33442424433).

The spelling of 12111213312 in words is "twelve billion, one hundred eleven million, two hundred thirteen thousand, three hundred twelve".