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12112010000 = 24543189439
BaseRepresentation
bin10110100011110111…
…01001101100010000
31011021002212212011222
423101323221230100
5144301133310000
65321510224212
7606101246336
oct132173515420
934232785158
1012112010000
115155a06422
122420355068
1311b0421a2c
1482c857b56
154ad4e8a85
hex2d1ee9b10

12112010000 has 200 divisors, whose sum is σ = 30680179200. Its totient is φ = 4625280000.

The previous prime is 12112009981. The next prime is 12112010003. The reversal of 12112010000 is 1021121.

12112010000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a self number, because there is not a number n which added to its sum of digits gives 12112010000.

It is not an unprimeable number, because it can be changed into a prime (12112010003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 27589781 + ... + 27590219.

It is an arithmetic number, because the mean of its divisors is an integer number (153400896).

Almost surely, 212112010000 is an apocalyptic number.

12112010000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12112010000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15340089600).

12112010000 is an abundant number, since it is smaller than the sum of its proper divisors (18568169200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12112010000 is an equidigital number, since it uses as much as digits as its factorization.

12112010000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 587 (or 566 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 12112010000 its reverse (1021121), we get a palindrome (12113031121).

The spelling of 12112010000 in words is "twelve billion, one hundred twelve million, ten thousand".